Home Physics Kinetic Theory of Gases JEE Main 2023 Match List I with List II: List IList II(A) …
Physics Kinetic Theory of Gases JEE Main 2023 MCQ (Single Correct)

Match List I with List II:

List I

List II

(A) 3 Translational degrees of freedom

(I) Monoatomic gases

(B) 3 Translational, 2 rotational degrees of freedoms

(II) Polyatomic gases

(C) 3 Translational, 2 rotational and 1 vibrational degrees of freedom

(III) Rigid diatomic gases

(D) 3 Translational, 3 rotational and more than one vibrational degrees of freedom

(IV) Nonrigid diatomic gases

Choose the correct answer from the options given below:

A
-(I), -(IV), -(IV), -(I),
B
-(III), -(III), -(II), -(IV),
C
-(IV), -(II), -(I), -(III),
D
-(II) -(I) -(III) -(II)

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Text Solution

Verified by Experts
The correct answer is:
A

The formula for degree of freedom is given by

f = 3N-k

where N is the number of particles, k is the individual relationship in the system.

For a monoatomic gas particle, N = 1, k = 0. So, f = 3

Hence, monoatomic gas has 3 translational degree of freedom.

For a rigid diatomic gas molecule, there are 5 degrees of freedom, 3 translational and 2 rotational. A diatomic gas can have two extra degrees of freedom due to rotation along two independent axes.

A non rigid diatomic molecule has one extra degree of freedom than a rigid one. This is the vibrational degree of freedom. Hence, it has 6 degrees of freedom.

So, a non rigid diatomic gas has 3 translational, 2 rotational and 1 vibrational degrees of freedom.

A polyatomic gas has more than two atoms per molecule. Hence, the total number of degrees of freedom is 3 translational, 3 rotational and more than one vibrational degree of freedom.

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